Board Licensure Examination for Professional Teachers Reviewer

EXERCISES IN MATHEMATICS

EXERCISE II

ANSWER AND SOLUTION

Problem 1.

Answers: 15 games

Loses 40 = .4 x 40 = 16 games

Wins 40 = 40 – 16 = 24 wins in the first 40 games

Total wins = 65% the games

W40 + W20 = 65(40+20) = 39.00

24 + W20 = 39

W20 = 39 – 24 – 15 games (answer)

Problem 2.

Answers: 28 days

Greater         : Less              =          Greater         : Less

40 students  : 10 students=         x days : 7 days

10 x                = 40 (7)

10x/10 = 280/10

x                      = 28 days

Problem 3.

Answers: N = 16

Let N = No. of divisions

240     =          4  (240)

N+4                5  N

I           =          4

N+4                5N

5N = 4N + 16

N = 16

Problem 4.

Answer: 15%

P680.00 – P575.00 = P105.00

P105.00 / P680.00 = .15

= 15%

Problem 5.

Answer: 4 qts.

% of water = 12 qts. - .2 (12) = 2.4 qts. Calamansi

Let W = added amount of water

2.4 / 12 + W = .15

1.8      + .15 W

W        =.6 / .15

W        = 4 qts.

Problem 6.

Answer: 10 men to be added

Let x = no. of men to finish in 4 days

20:x = 4:6

4x = 120

x = 30 men to finish in 4 days

30 -2- = 10 men to be added

Problem 7.

Answer: 9

Let N              = 1st group

24 – N            = other groups

N – (24 – N) = 6

N – 24 + H    = 6

2N                   = 30

N                     = 15

24 – N            = 9

Problem 8.

Answer: 20

Let T               = total time

T – (3/10) T = 14

7/10 T            = 14

T          = 140/7

T          = 20

Problem 9.

Answer: 1.22 hours

Ratio of A = 200 (converted to hrs.) / 2.3 hrs = 87 hrs.

Ratio of B = 200 / 2.6 hrs = 77 hrs.

Combining A & B = 164 hours

Time for 200 combined = 200/164 = 1.22 hours

Problem 10.

Answer: 45 hectares for the eldest son’s share

1 + 2 + 3        = 6 equals parcels of lot

Let N              = area of lot or share

6N/6              = 90 hectares / 6

N                     = 15 hectares for the youngest son’s share

2 N                  = 2 (15)

= 30 hectares for the middle son’s share

3 N                  = 3 (15)

= 45 hectares for the eldest son’s share

Problem 11.

Answer: d 487.50

C1       :           C2       = hb1: hb2

P780  :           C2       = 120:75

120c                           = 780(75)

120c / 120               = 58500 / 120

C                                  = P487.50

Problem 12.

Answer: a. 1,512

Let N  = no. of workers retained

16 N   = 288

N         = 288 / 16

N         = 1,800

= 1800 – 288

= 1,512